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56.25-x^2=0
We add all the numbers together, and all the variables
-1x^2+56.25=0
a = -1; b = 0; c = +56.25;
Δ = b2-4ac
Δ = 02-4·(-1)·56.25
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-15}{2*-1}=\frac{-15}{-2} =7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+15}{2*-1}=\frac{15}{-2} =-7+1/2 $
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